v^2-10v-16=0

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Solution for v^2-10v-16=0 equation:


Simplifying
v2 + -10v + -16 = 0

Reorder the terms:
-16 + -10v + v2 = 0

Solving
-16 + -10v + v2 = 0

Solving for variable 'v'.

Begin completing the square.

Move the constant term to the right:

Add '16' to each side of the equation.
-16 + -10v + 16 + v2 = 0 + 16

Reorder the terms:
-16 + 16 + -10v + v2 = 0 + 16

Combine like terms: -16 + 16 = 0
0 + -10v + v2 = 0 + 16
-10v + v2 = 0 + 16

Combine like terms: 0 + 16 = 16
-10v + v2 = 16

The v term is -10v.  Take half its coefficient (-5).
Square it (25) and add it to both sides.

Add '25' to each side of the equation.
-10v + 25 + v2 = 16 + 25

Reorder the terms:
25 + -10v + v2 = 16 + 25

Combine like terms: 16 + 25 = 41
25 + -10v + v2 = 41

Factor a perfect square on the left side:
(v + -5)(v + -5) = 41

Calculate the square root of the right side: 6.403124237

Break this problem into two subproblems by setting 
(v + -5) equal to 6.403124237 and -6.403124237.

Subproblem 1

v + -5 = 6.403124237 Simplifying v + -5 = 6.403124237 Reorder the terms: -5 + v = 6.403124237 Solving -5 + v = 6.403124237 Solving for variable 'v'. Move all terms containing v to the left, all other terms to the right. Add '5' to each side of the equation. -5 + 5 + v = 6.403124237 + 5 Combine like terms: -5 + 5 = 0 0 + v = 6.403124237 + 5 v = 6.403124237 + 5 Combine like terms: 6.403124237 + 5 = 11.403124237 v = 11.403124237 Simplifying v = 11.403124237

Subproblem 2

v + -5 = -6.403124237 Simplifying v + -5 = -6.403124237 Reorder the terms: -5 + v = -6.403124237 Solving -5 + v = -6.403124237 Solving for variable 'v'. Move all terms containing v to the left, all other terms to the right. Add '5' to each side of the equation. -5 + 5 + v = -6.403124237 + 5 Combine like terms: -5 + 5 = 0 0 + v = -6.403124237 + 5 v = -6.403124237 + 5 Combine like terms: -6.403124237 + 5 = -1.403124237 v = -1.403124237 Simplifying v = -1.403124237

Solution

The solution to the problem is based on the solutions from the subproblems. v = {11.403124237, -1.403124237}

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